String postResp = post. HttpClient httpclient = new HttpClient() tRequestEntity(new MultipartRequestEntity(fields,post.getParams())) PostMethod post =new PostMethod(targetURL) PartSource ps = new ByteArrayPartSource(file,fbArray) This will add the parent directory of alembic/ to your PYTHONPATH so that it can find the models module. TargetURL = targetURL + "?authtoken="+ auth_token +"&scope="+ auth_scope With the project structure you've outlined, it might be a little hard to address the easiest solution might be to modify your PYTHONPATH inside env.py like this: import sys sys.path '', '.' + sys.path 1: from models import Base. The File Path i.e the location of the FileįileInputStream fis = new FileInputStream(f) īyteArrayOutputStream bos = new ByteArrayOutputStream().The uploadFile Request URL in the format mentioned above.In the program, you need to specify values for the following: You can run this program in your Java Environment to upload a file to a record. In the case of the parameter attachmentUrl, content is not required as the attachment is from a URL.Įxample for attachmentUrl: crm/private/xml/Leads/uploadFile?authtoken=*****&scope=crmapi&id=&attachmentUrl=.Files can be attached to records in all modules except Reports, Dashboards and Forecasts.The attached file will be available under the Attachments section in the Record Details Page.This limit does not apply to URLs attached via attachmentUrl. If the size exceeds 20 MB, you will receive the following error message: " File size should not exceed 20 MB".If API User requests more than 60 calls, system will block the API access for 5 min.
Your program can request only up to 60 uploadFile calls per min.The total file size should not exceed 20 MB.
0 kommentar(er)
